In the circuit shown in figure –

Text Solution
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CHECK THE SOLUTION.
(a, c)
4 Ω Ω and 6 Ω Ω resistance are short circuited. Therefore, no current will flow through these two resistances. Current passing through the battery is
i =
= 10 A
This is also the current passing in wire AB from B to A.
Power supplied by the battery P = E i
(20) (10)
= 200 W
Potential difference across 4 Ω Ω resistance
= potential difference across 6 Ω Ω resistance = 0
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